点集拓扑复习 -- Locally Compact Hausdorff
在这篇文章里, 我们会复习一些点集拓扑的概念, 包括但不限于:
- 什么是正则 (regular) 和正规 (normal) 空间.
- 正则空间和正规空间的等价定义.
- 局部紧致空间的局部具有一些歧义, 但是在 Hausdorff 的时候就不会有这样的问题.
- 流形 is paracompact (仿紧).
正则空间和正规空间
设 $X$ 是一个拓扑空间, 我们称 $X$
- 正则, 如果我们能用开集来区分一个点和闭集.
- 正规, 如果我们能用开集来区分不相交的两个闭集.
-
$X$ is regular if and only if for all $x \in U$ with $U$ open, there exists $V$ open such that $x \in V \subseteq \ol{V} \subseteq U$.
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$X$ is normal if and only if for all $A \subseteq E \subset X$ with $A$ closed and $E$ open, there exists $V$ open such that $A \subseteq V \subseteq \ol{V} \subseteq E$.
Conversely, let $A, B$ be disjoint closed set, we can choose $V$ open such that $A \subseteq V \subseteq \ol{V} \subseteq B^c$. Then $V$ and $X - \ol{V}$ separate $A$ and $B$.
(1) 证明类似, 省略. $\square$
证明中用到了下述关键性质:
真是惭愧, 仔细回想, 这两个结论老夫当初学拓扑的时候肯定学过, 可以说是 regular 和 normal space 的等价定义, 然而不是今天刚好 review, 我真是几乎忘掉了.
局部紧致空间的歧义
$X$ is said to be locally (path) connected if every point admits a neighbourhood basis consisting entirely of open, (path) connected sets. 但是非常无语的是, $X$ is said to be locally compact if every point $x$ of $X$ has a compact neighbourhood. 有没有人可以告诉我, 为什么 locally compact 的定义要求存在一个紧致邻域就够了, 但是 locally connected 就要求存在一组邻域基呢?
不过幸运的是, 当 $X$ 是 Hausdorff 的时候, 存在一个紧致邻域和存在紧致邻域基是一回事, 因此不会产生歧义.
Assume $X$ is Hausdorff, the following are equivalent:
- every point of $X$ has a compact neighbourhood.
- every point of $X$ has a local base of compact neighbourhoods.
- 紧致空间的闭子集紧致.
- Hausdorff 空间中的紧集是闭集. See MSE 83355 or [1, 3.5.6 (Corollary 4)] .
- The subspace of Hausdorff space is agian Hausdorff.
- Compact Hausdorff implies normal (a fortiori, regular) c.f. [1, 3.5.5 and 3.5.6 (Corollary 3)] .
Let $X$ be a locally compact Hausdorff space. For any basis $\CB$, the family
$$ \CB_c := \{U \in \CB: \ol{U} \text{ is compact}\} $$
is also a basis. 换句话说, 对于局部紧致的 Hausdorff 空间, 我们总是可以不妨假设它的拓扑基都有 compact closure.
最后我们再给出一个定理, 该定理说明了任意流形都是仿紧的, 我们会在单位分解定理的证明中使用这个结论.
因为当 $i - j \ge 3$ 的时候, $$ G_{i+1} - \overline{G_{i-2}} \cap G_{j+1} - \overline{G_{j-2}} = \varnothing. $$ 所以最后构造出的 refinement 是 locally finite $\square$
References
- 1
- Ronald Brown. Topology and Groupoids. http://groupoids.org.uk/pdffiles/topgrpds-e.pdf
- 2
- Frank W. Warner. Foundations of Differentiable Manifolds and Lie Groups. GTM 94.